Number of Mismatch Nodes in G₃(5, n)

n = 5 … 100  ·  k = 5  ·  source A = 0⁵1n−5  ·  t(n) = C(n,5)  ·  asymptote m/t → 7/32 = 0.21875

t(n) = C(n, 5)  (total vertices)
m(n) = C(⌊n/2⌋, 5) + C(⌈n/2⌉, 5) + C(⌊n/2⌋, 4)·⌈n/2⌉  (mismatch vertices)
ratio = m/t → 7/32 ≈ 0.21875  as n → ∞   (bar width scaled to asymptote 7/32)
Mismatch geometric families (7 parity patterns → 3 families)
All 5 zeros at even positions Δ = 3 C(⌊n/2⌋, 5) ways
All 5 zeros at odd positions Δ = 2 C(⌈n/2⌉, 5) ways
Exactly 4 even + 1 odd zero Δ = 2 C(⌊n/2⌋, 4)·⌈n/2⌉ ways